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4-2/3x=2x
We move all terms to the left:
4-2/3x-(2x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-2x-2/3x+4=0
We multiply all the terms by the denominator
-2x*3x+4*3x-2=0
Wy multiply elements
-6x^2+12x-2=0
a = -6; b = 12; c = -2;
Δ = b2-4ac
Δ = 122-4·(-6)·(-2)
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{6}}{2*-6}=\frac{-12-4\sqrt{6}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{6}}{2*-6}=\frac{-12+4\sqrt{6}}{-12} $
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