4-2(z-4)=1/2(2z+5)

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Solution for 4-2(z-4)=1/2(2z+5) equation: 



4-2(z-4)=1/2(2z+5)

We move all terms to the left:

4-2(z-4)-(1/2(2z+5))=0



Domain of the equation: 2(2z+5))!=0

z∈R



We multiply parentheses

-2z-(1/2(2z+5))+8+4=0

We multiply all the terms by the denominator


-2z*2(2z+5))-(1+8*2(2z+5))+4*2(2z+5))=0

We add all the numbers together, and all the variables

-2z*2(2z+5))-(1+8*2(2z+5))+4*2(2z=0

Wy multiply elements

-4z^2(2+32z^2(2=0

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