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(7x-4)(3x-2)=0
We multiply parentheses ..
(+21x^2-14x-12x+8)=0
We get rid of parentheses
21x^2-14x-12x+8=0
We add all the numbers together, and all the variables
21x^2-26x+8=0
a = 21; b = -26; c = +8;
Δ = b2-4ac
Δ = -262-4·21·8
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2}{2*21}=\frac{24}{42} =4/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2}{2*21}=\frac{28}{42} =2/3 $
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