4-2(4y+3)=-(1-2y)

Solution for 4-2(4y+3)=-(1-2y) equation:

4-2(4y+3)=-(1-2y)

We move all terms to the left:

4-2(4y+3)-(-(1-2y))=0

We add all the numbers together, and all the variables

-2(4y+3)-(-(-2y+1))+4=0

We multiply parentheses

-8y-(-(-2y+1))-6+4=0


We calculate terms in parentheses: -(-(-2y+1)), so:

-(-2y+1)

We get rid of parentheses

2y-1

Back to the equation:

-(2y-1)


We add all the numbers together, and all the variables

-8y-(2y-1)-2=0

We get rid of parentheses

-8y-2y+1-2=0

We add all the numbers together, and all the variables

-10y-1=0

We move all terms containing y to the left, all other terms to the right

-10y=1

y=1/-10

y=-1/10