4-2(3y+1)=14

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Solution for 4-2(3y+1)=14 equation: 



4-2(3y+1)=14

We move all terms to the left:

4-2(3y+1)-(14)=0

We add all the numbers together, and all the variables

-2(3y+1)-10=0

We multiply parentheses

-6y-2-10=0

We add all the numbers together, and all the variables

-6y-12=0

We move all terms containing y to the left, all other terms to the right

-6y=12

y=12/-6

y=-2

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