1/2(4x-12)=1/4(16-20x)

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Solution for 1/2(4x-12)=1/4(16-20x) equation: 



1/2(4x-12)=1/4(16-20x)

We move all terms to the left:

1/2(4x-12)-(1/4(16-20x))=0



Domain of the equation: 2(4x-12)!=0

x∈R





Domain of the equation: 4(16-20x))!=0

x∈R



We add all the numbers together, and all the variables

1/2(4x-12)-(1/4(-20x+16))=0

We calculate fractions


(4x(-)/(2(4x-12)*4(-20x+16)))+(-2x4/(2(4x-12)*4(-20x+16)))=0



We calculate terms in parentheses: +(4x(-)/(2(4x-12)*4(-20x+16))), so:

4x(-)/(2(4x-12)*4(-20x+16))

We add all the numbers together, and all the variables

4x0/(2(4x-12)*4(-20x+16))

We multiply all the terms by the denominator


4x0

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)





We calculate terms in parentheses: +(-2x4/(2(4x-12)*4(-20x+16))), so:

-2x4/(2(4x-12)*4(-20x+16))

We multiply all the terms by the denominator


-2x4

We add all the numbers together, and all the variables

-2x^4

We do not support expression: x^4

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