4-2(3x+4)=4x+12

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Solution for 4-2(3x+4)=4x+12 equation: 



4-2(3x+4)=4x+12

We move all terms to the left:

4-2(3x+4)-(4x+12)=0

We multiply parentheses

-6x-(4x+12)-8+4=0

We get rid of parentheses

-6x-4x-12-8+4=0

We add all the numbers together, and all the variables

-10x-16=0

We move all terms containing x to the left, all other terms to the right

-10x=16

x=16/-10

x=-1+3/5

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