4-12+3y=4(2y-7)+5

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Solution for 4-12+3y=4(2y-7)+5 equation: 



4-12+3y=4(2y-7)+5

We move all terms to the left:

4-12+3y-(4(2y-7)+5)=0

We add all the numbers together, and all the variables

3y-(4(2y-7)+5)-8=0



We calculate terms in parentheses: -(4(2y-7)+5), so:

4(2y-7)+5

We multiply parentheses

8y-28+5

We add all the numbers together, and all the variables

8y-23

Back to the equation:

-(8y-23)



We get rid of parentheses

3y-8y+23-8=0

We add all the numbers together, and all the variables

-5y+15=0

We move all terms containing y to the left, all other terms to the right

-5y=-15

y=-15/-5

y=+3

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