3(6-a)-33=17a-5(3+4a)

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Solution for 3(6-a)-33=17a-5(3+4a) equation: 



3(6-a)-33=17a-5(3+4a)

We move all terms to the left:

3(6-a)-33-(17a-5(3+4a))=0

We add all the numbers together, and all the variables

3(-1a+6)-(17a-5(4a+3))-33=0

We multiply parentheses

-3a-(17a-5(4a+3))+18-33=0



We calculate terms in parentheses: -(17a-5(4a+3)), so:

17a-5(4a+3)

We multiply parentheses

17a-20a-15

We add all the numbers together, and all the variables

-3a-15

Back to the equation:

-(-3a-15)



We add all the numbers together, and all the variables

-3a-(-3a-15)-15=0

We get rid of parentheses

-3a+3a+15-15=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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