4-(x-2)+3(2x-5)=11

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Solution for 4-(x-2)+3(2x-5)=11 equation: 



4-(x-2)+3(2x-5)=11

We move all terms to the left:

4-(x-2)+3(2x-5)-(11)=0

We add all the numbers together, and all the variables

-(x-2)+3(2x-5)-7=0

We multiply parentheses

-(x-2)+6x-15-7=0

We get rid of parentheses

-x+6x+2-15-7=0

We add all the numbers together, and all the variables

5x-20=0

We move all terms containing x to the left, all other terms to the right

5x=20

x=20/5

x=4

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