(3x-4)=(20x+8)

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Solution for (3x-4)=(20x+8) equation: 



(3x-4)=(20x+8)

We move all terms to the left:

(3x-4)-((20x+8))=0

We get rid of parentheses

3x-((20x+8))-4=0



We calculate terms in parentheses: -((20x+8)), so:

(20x+8)

We get rid of parentheses

20x+8

Back to the equation:

-(20x+8)



We get rid of parentheses

3x-20x-8-4=0

We add all the numbers together, and all the variables

-17x-12=0

We move all terms containing x to the left, all other terms to the right

-17x=12

x=12/-17

x=-12/17

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