4-(3+f)6f=-24

Solution for 4-(3+f)6f=-24 equation:

4-(3+f)6f=-24

We move all terms to the left:

4-(3+f)6f-(-24)=0

We add all the numbers together, and all the variables

-(f+3)6f+4-(-24)=0

We add all the numbers together, and all the variables

-(f+3)6f+28=0

We multiply parentheses

-6f^2-18f+28=0

a = -6; b = -18; c = +28;
Δ = b2-4ac
Δ = -182-4·(-6)·28
Δ = 996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{996}=\sqrt{4*249}=\sqrt{4}*\sqrt{249}=2\sqrt{249}$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{249}}{2*-6}=\frac{18-2\sqrt{249}}{-12}
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{249}}{2*-6}=\frac{18+2\sqrt{249}}{-12}
$