-2x2+7x+2=0

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Solution for -2x2+7x+2=0 equation: 



-2x^2+7x+2=0

a = -2; b = 7; c = +2;
Δ = b2-4ac
Δ = 72-4·(-2)·2
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{65}}{2*-2}=\frac{-7-\sqrt{65}}{-4}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{65}}{2*-2}=\frac{-7+\sqrt{65}}{-4}
$

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