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4+6(x+1)=4x+(x-5)
We move all terms to the left:
4+6(x+1)-(4x+(x-5))=0
We multiply parentheses
6x-(4x+(x-5))+6+4=0
We calculate terms in parentheses: -(4x+(x-5)), so:We add all the numbers together, and all the variables
4x+(x-5)
We get rid of parentheses
4x+x-5
We add all the numbers together, and all the variables
5x-5
Back to the equation:
-(5x-5)
6x-(5x-5)+10=0
We get rid of parentheses
6x-5x+5+10=0
We add all the numbers together, and all the variables
x+15=0
We move all terms containing x to the left, all other terms to the right
x=-15
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