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5x^2=12
We move all terms to the left:
5x^2-(12)=0
a = 5; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·5·(-12)
Δ = 240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{240}=\sqrt{16*15}=\sqrt{16}*\sqrt{15}=4\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{15}}{2*5}=\frac{0-4\sqrt{15}}{10} =-\frac{4\sqrt{15}}{10} =-\frac{2\sqrt{15}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{15}}{2*5}=\frac{0+4\sqrt{15}}{10} =\frac{4\sqrt{15}}{10} =\frac{2\sqrt{15}}{5} $
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