4+5(x-2)=3+4(2-x)-10

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Solution for 4+5(x-2)=3+4(2-x)-10 equation: 



4+5(x-2)=3+4(2-x)-10

We move all terms to the left:

4+5(x-2)-(3+4(2-x)-10)=0

We add all the numbers together, and all the variables

5(x-2)-(3+4(-1x+2)-10)+4=0

We multiply parentheses

5x-(3+4(-1x+2)-10)-10+4=0



We calculate terms in parentheses: -(3+4(-1x+2)-10), so:

3+4(-1x+2)-10

determiningTheFunctionDomain
4(-1x+2)+3-10

We add all the numbers together, and all the variables

4(-1x+2)-7

We multiply parentheses

-4x+8-7

We add all the numbers together, and all the variables

-4x+1

Back to the equation:

-(-4x+1)



We add all the numbers together, and all the variables

5x-(-4x+1)-6=0

We get rid of parentheses

5x+4x-1-6=0

We add all the numbers together, and all the variables

9x-7=0

We move all terms containing x to the left, all other terms to the right

9x=7

x=7/9

x=7/9

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