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x(30+x)=99
We move all terms to the left:
x(30+x)-(99)=0
We add all the numbers together, and all the variables
x(x+30)-99=0
We multiply parentheses
x^2+30x-99=0
a = 1; b = 30; c = -99;
Δ = b2-4ac
Δ = 302-4·1·(-99)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-36}{2*1}=\frac{-66}{2} =-33 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+36}{2*1}=\frac{6}{2} =3 $
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