4+4m=2m+4(m+2)

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Solution for 4+4m=2m+4(m+2) equation: 



4+4m=2m+4(m+2)

We move all terms to the left:

4+4m-(2m+4(m+2))=0



We calculate terms in parentheses: -(2m+4(m+2)), so:

2m+4(m+2)

We multiply parentheses

2m+4m+8

We add all the numbers together, and all the variables

6m+8

Back to the equation:

-(6m+8)



We get rid of parentheses

4m-6m-8+4=0

We add all the numbers together, and all the variables

-2m-4=0

We move all terms containing m to the left, all other terms to the right

-2m=4

m=4/-2

m=-2

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