285=7(1-5v)-2

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Solution for 285=7(1-5v)-2 equation: 



285=7(1-5v)-2

We move all terms to the left:

285-(7(1-5v)-2)=0

We add all the numbers together, and all the variables

-(7(-5v+1)-2)+285=0



We calculate terms in parentheses: -(7(-5v+1)-2), so:

7(-5v+1)-2

We multiply parentheses

-35v+7-2

We add all the numbers together, and all the variables

-35v+5

Back to the equation:

-(-35v+5)



We get rid of parentheses

35v-5+285=0

We add all the numbers together, and all the variables

35v+280=0

We move all terms containing v to the left, all other terms to the right

35v=-280

v=-280/35

v=-8

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