3n-2(3+3n)=-5(2n+4)

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Solution for 3n-2(3+3n)=-5(2n+4) equation: 



3n-2(3+3n)=-5(2n+4)

We move all terms to the left:

3n-2(3+3n)-(-5(2n+4))=0

We add all the numbers together, and all the variables

3n-2(3n+3)-(-5(2n+4))=0

We multiply parentheses

3n-6n-(-5(2n+4))-6=0



We calculate terms in parentheses: -(-5(2n+4)), so:

-5(2n+4)

We multiply parentheses

-10n-20

Back to the equation:

-(-10n-20)



We add all the numbers together, and all the variables

-3n-(-10n-20)-6=0

We get rid of parentheses

-3n+10n+20-6=0

We add all the numbers together, and all the variables

7n+14=0

We move all terms containing n to the left, all other terms to the right

7n=-14

n=-14/7

n=-2

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