4+2x=2(2x+4)-3(x-2)

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Solution for 4+2x=2(2x+4)-3(x-2) equation: 



4+2x=2(2x+4)-3(x-2)

We move all terms to the left:

4+2x-(2(2x+4)-3(x-2))=0



We calculate terms in parentheses: -(2(2x+4)-3(x-2)), so:

2(2x+4)-3(x-2)

We multiply parentheses

4x-3x+8+6

We add all the numbers together, and all the variables

x+14

Back to the equation:

-(x+14)



We get rid of parentheses

2x-x-14+4=0

We add all the numbers together, and all the variables

x-10=0

We move all terms containing x to the left, all other terms to the right

x=10

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