(2x-2)+2(3x+8)=4x-2

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Solution for (2x-2)+2(3x+8)=4x-2 equation: 



(2x-2)+2(3x+8)=4x-2

We move all terms to the left:

(2x-2)+2(3x+8)-(4x-2)=0

We multiply parentheses

(2x-2)+6x-(4x-2)+16=0

We get rid of parentheses

2x+6x-4x-2+2+16=0

We add all the numbers together, and all the variables

4x+16=0

We move all terms containing x to the left, all other terms to the right

4x=-16

x=-16/4

x=-4

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