4+2(x+4)=6-3(x-1)

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Solution for 4+2(x+4)=6-3(x-1) equation: 



4+2(x+4)=6-3(x-1)

We move all terms to the left:

4+2(x+4)-(6-3(x-1))=0

We multiply parentheses

2x-(6-3(x-1))+8+4=0



We calculate terms in parentheses: -(6-3(x-1)), so:

6-3(x-1)

determiningTheFunctionDomain
-3(x-1)+6

We multiply parentheses

-3x+3+6

We add all the numbers together, and all the variables

-3x+9

Back to the equation:

-(-3x+9)



We add all the numbers together, and all the variables

2x-(-3x+9)+12=0

We get rid of parentheses

2x+3x-9+12=0

We add all the numbers together, and all the variables

5x+3=0

We move all terms containing x to the left, all other terms to the right

5x=-3

x=-3/5

x=-3/5

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