3+2(k-+1)=3k+6

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Solution for 3+2(k-+1)=3k+6 equation: 



3+2(k-+1)=3k+6

We move all terms to the left:

3+2(k-+1)-(3k+6)=0

We add all the numbers together, and all the variables

2(+k)-(3k+6)+3=0

We multiply parentheses

2k-(3k+6)+3=0

We get rid of parentheses

2k-3k-6+3=0

We add all the numbers together, and all the variables

-1k-3=0

We move all terms containing k to the left, all other terms to the right

-k=3

k=3/-1

k=-3

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