4+(3x+2)=68

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Solution for 4+(3x+2)=68 equation: 



4+(3x+2)=68

We move all terms to the left:

4+(3x+2)-(68)=0

We add all the numbers together, and all the variables

(3x+2)-64=0

We get rid of parentheses

3x+2-64=0

We add all the numbers together, and all the variables

3x-62=0

We move all terms containing x to the left, all other terms to the right

3x=62

x=62/3

x=20+2/3

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