20=(7)/(5)h+16-12-5

Solution for 20=(7)/(5)h+16-12-5 equation:

20=(7)/(5)h+16-12-5

We move all terms to the left:

20-((7)/(5)h+16-12-5)=0


Domain of the equation: 5h+16-12-5)!=0

We move all terms containing h to the left, all other terms to the right

5h-5)!=-4

h∈R


We add all the numbers together, and all the variables

-(7/5h-1)+20=0

We get rid of parentheses

-7/5h+1+20=0

We multiply all the terms by the denominator


1*5h+20*5h-7=0

Wy multiply elements

5h+100h-7=0

We add all the numbers together, and all the variables

105h-7=0

We move all terms containing h to the left, all other terms to the right

105h=7

h=7/105

h=1/15