33=-3(1+b)

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Solution for 33=-3(1+b) equation: 



33=-3(1+b)

We move all terms to the left:

33-(-3(1+b))=0

We add all the numbers together, and all the variables

-(-3(b+1))+33=0



We calculate terms in parentheses: -(-3(b+1)), so:

-3(b+1)

We multiply parentheses

-3b-3

Back to the equation:

-(-3b-3)



We get rid of parentheses

3b+3+33=0

We add all the numbers together, and all the variables

3b+36=0

We move all terms containing b to the left, all other terms to the right

3b=-36

b=-36/3

b=-12

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