4+(1/5)b=(3/10)b

Solution for 4+(1/5)b=(3/10)b equation:

4+(1/5)b=(3/10)b

We move all terms to the left:

4+(1/5)b-((3/10)b)=0


Domain of the equation: 5)b!=0

b!=0/1

b!=0

b∈R



Domain of the equation: 10)b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

(+1/5)b-((+3/10)b)+4=0

We multiply parentheses

b^2-((+3/10)b)+4=0

We multiply all the terms by the denominator


b^2*10)b)-((+4*10)b)+3=0

We add all the numbers together, and all the variables

b^2*10)b)-(40b)+3=0

We add all the numbers together, and all the variables

b^2*10)b)-40b+3=0

Wy multiply elements

10b^3=0

We do not support ebpression: b^3