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(2/3)x+4=-2+x
We move all terms to the left:
(2/3)x+4-(-2+x)=0
Domain of the equation: 3)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/3)x-(x-2)+4=0
We multiply parentheses
2x^2-(x-2)+4=0
We get rid of parentheses
2x^2-x+2+4=0
We add all the numbers together, and all the variables
2x^2-1x+6=0
a = 2; b = -1; c = +6;
Δ = b2-4ac
Δ = -12-4·2·6
Δ = -47
Delta is less than zero, so there is no solution for the equation
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