4(z-2)+6=10

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Solution for 4(z-2)+6=10 equation: 



4(z-2)+6=10

We move all terms to the left:

4(z-2)+6-(10)=0

We add all the numbers together, and all the variables

4(z-2)-4=0

We multiply parentheses

4z-8-4=0

We add all the numbers together, and all the variables

4z-12=0

We move all terms containing z to the left, all other terms to the right

4z=12

z=12/4

z=3

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