5(2c+7)=10c+40-5

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Solution for 5(2c+7)=10c+40-5 equation: 



5(2c+7)=10c+40-5

We move all terms to the left:

5(2c+7)-(10c+40-5)=0

We add all the numbers together, and all the variables

5(2c+7)-(10c+35)=0

We multiply parentheses

10c-(10c+35)+35=0

We get rid of parentheses

10c-10c-35+35=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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