4(z+5)+6(2z-3)=12

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Solution for 4(z+5)+6(2z-3)=12 equation: 



4(z+5)+6(2z-3)=12

We move all terms to the left:

4(z+5)+6(2z-3)-(12)=0

We multiply parentheses

4z+12z+20-18-12=0

We add all the numbers together, and all the variables

16z-10=0

We move all terms containing z to the left, all other terms to the right

16z=10

z=10/16

z=5/8

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