3(2x-5)=4(x-4)+2x+1

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Solution for 3(2x-5)=4(x-4)+2x+1 equation: 



3(2x-5)=4(x-4)+2x+1

We move all terms to the left:

3(2x-5)-(4(x-4)+2x+1)=0

We multiply parentheses

6x-(4(x-4)+2x+1)-15=0



We calculate terms in parentheses: -(4(x-4)+2x+1), so:

4(x-4)+2x+1

We add all the numbers together, and all the variables

2x+4(x-4)+1

We multiply parentheses

2x+4x-16+1

We add all the numbers together, and all the variables

6x-15

Back to the equation:

-(6x-15)



We get rid of parentheses

6x-6x+15-15=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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