4(z+2)=2(z-6)

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Solution for 4(z+2)=2(z-6) equation: 



4(z+2)=2(z-6)

We move all terms to the left:

4(z+2)-(2(z-6))=0

We multiply parentheses

4z-(2(z-6))+8=0



We calculate terms in parentheses: -(2(z-6)), so:

2(z-6)

We multiply parentheses

2z-12

Back to the equation:

-(2z-12)



We get rid of parentheses

4z-2z+12+8=0

We add all the numbers together, and all the variables

2z+20=0

We move all terms containing z to the left, all other terms to the right

2z=-20

z=-20/2

z=-10

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