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X(4X-6)=40
We move all terms to the left:
X(4X-6)-(40)=0
We multiply parentheses
4X^2-6X-40=0
a = 4; b = -6; c = -40;
Δ = b2-4ac
Δ = -62-4·4·(-40)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-26}{2*4}=\frac{-20}{8} =-2+1/2 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+26}{2*4}=\frac{32}{8} =4 $
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