4(y-3)=6y-12-2y

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Solution for 4(y-3)=6y-12-2y equation: 



4(y-3)=6y-12-2y

We move all terms to the left:

4(y-3)-(6y-12-2y)=0

We add all the numbers together, and all the variables

4(y-3)-(4y-12)=0

We multiply parentheses

4y-(4y-12)-12=0

We get rid of parentheses

4y-4y+12-12=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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