10+3(4x-5)=15x+40

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Solution for 10+3(4x-5)=15x+40 equation: 



10+3(4x-5)=15x+40

We move all terms to the left:

10+3(4x-5)-(15x+40)=0

We multiply parentheses

12x-(15x+40)-15+10=0

We get rid of parentheses

12x-15x-40-15+10=0

We add all the numbers together, and all the variables

-3x-45=0

We move all terms containing x to the left, all other terms to the right

-3x=45

x=45/-3

x=-15

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