4(y-3)-4=-2(-8y+2)-2y

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Solution for 4(y-3)-4=-2(-8y+2)-2y equation: 



4(y-3)-4=-2(-8y+2)-2y

We move all terms to the left:

4(y-3)-4-(-2(-8y+2)-2y)=0

We multiply parentheses

4y-(-2(-8y+2)-2y)-12-4=0



We calculate terms in parentheses: -(-2(-8y+2)-2y), so:

-2(-8y+2)-2y

We add all the numbers together, and all the variables

-2y-2(-8y+2)

We multiply parentheses

-2y+16y-4

We add all the numbers together, and all the variables

14y-4

Back to the equation:

-(14y-4)



We add all the numbers together, and all the variables

4y-(14y-4)-16=0

We get rid of parentheses

4y-14y+4-16=0

We add all the numbers together, and all the variables

-10y-12=0

We move all terms containing y to the left, all other terms to the right

-10y=12

y=12/-10

y=-1+1/5

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