3+4(t+2)=2t-3(2+4

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Solution for 3+4(t+2)=2t-3(2+4 equation: 



3+4(t+2)=2t-3(2+4

We move all terms to the left:

3+4(t+2)-(2t-3(2+4)=0

We add all the numbers together, and all the variables

4(t+2)-(2t-36+3=0

We multiply parentheses

4t-(2t-36+3+8=0

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