4(y-3)+2=6

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Solution for 4(y-3)+2=6 equation: 



4(y-3)+2=6

We move all terms to the left:

4(y-3)+2-(6)=0

We add all the numbers together, and all the variables

4(y-3)-4=0

We multiply parentheses

4y-12-4=0

We add all the numbers together, and all the variables

4y-16=0

We move all terms containing y to the left, all other terms to the right

4y=16

y=16/4

y=4

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