4(y-2)+1=y-6+3y

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Solution for 4(y-2)+1=y-6+3y equation: 



4(y-2)+1=y-6+3y

We move all terms to the left:

4(y-2)+1-(y-6+3y)=0

We add all the numbers together, and all the variables

4(y-2)-(4y-6)+1=0

We multiply parentheses

4y-(4y-6)-8+1=0

We get rid of parentheses

4y-4y+6-8+1=0

We add all the numbers together, and all the variables

-1!=0

There is no solution for this equation

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