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4(y-1)=2(y+2)
We move all terms to the left:
4(y-1)-(2(y+2))=0
We multiply parentheses
4y-(2(y+2))-4=0
We calculate terms in parentheses: -(2(y+2)), so:We get rid of parentheses
2(y+2)
We multiply parentheses
2y+4
Back to the equation:
-(2y+4)
4y-2y-4-4=0
We add all the numbers together, and all the variables
2y-8=0
We move all terms containing y to the left, all other terms to the right
2y=8
y=8/2
y=4
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