2/3(a+1)=a.6

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Solution for 2/3(a+1)=a.6 equation: 



2/3(a+1)=a.6

We move all terms to the left:

2/3(a+1)-(a.6)=0



Domain of the equation: 3(a+1)!=0

a∈R



We add all the numbers together, and all the variables

2/3(a+1)-(+a.6)=0

We get rid of parentheses

2/3(a+1)-a.6=0

We multiply all the terms by the denominator


-(a.6)*3(a+1)+2=0

We add all the numbers together, and all the variables

-(+a.6)*3(a+1)+2=0

We move all terms containing a to the left, all other terms to the right

-(+a.6)*3(a+1)=-2

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