4(y-1)+2(y+3)=13

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Solution for 4(y-1)+2(y+3)=13 equation: 



4(y-1)+2(y+3)=13

We move all terms to the left:

4(y-1)+2(y+3)-(13)=0

We multiply parentheses

4y+2y-4+6-13=0

We add all the numbers together, and all the variables

6y-11=0

We move all terms containing y to the left, all other terms to the right

6y=11

y=11/6

y=1+5/6

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