5(3+4r)=-13(1-r)

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Solution for 5(3+4r)=-13(1-r) equation: 



5(3+4r)=-13(1-r)

We move all terms to the left:

5(3+4r)-(-13(1-r))=0

We add all the numbers together, and all the variables

5(4r+3)-(-13(-1r+1))=0

We multiply parentheses

20r-(-13(-1r+1))+15=0



We calculate terms in parentheses: -(-13(-1r+1)), so:

-13(-1r+1)

We multiply parentheses

13r-13

Back to the equation:

-(13r-13)



We get rid of parentheses

20r-13r+13+15=0

We add all the numbers together, and all the variables

7r+28=0

We move all terms containing r to the left, all other terms to the right

7r=-28

r=-28/7

r=-4

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