4(y+5-y+2y+5y+20)=320

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Solution for 4(y+5-y+2y+5y+20)=320 equation: 



4(y+5-y+2y+5y+20)=320

We move all terms to the left:

4(y+5-y+2y+5y+20)-(320)=0

We add all the numbers together, and all the variables

4(7y+25)-320=0

We multiply parentheses

28y+100-320=0

We add all the numbers together, and all the variables

28y-220=0

We move all terms containing y to the left, all other terms to the right

28y=220

y=220/28

y=7+6/7

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