4(y+4)=-2(5y-7)+8y

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Solution for 4(y+4)=-2(5y-7)+8y equation: 



4(y+4)=-2(5y-7)+8y

We move all terms to the left:

4(y+4)-(-2(5y-7)+8y)=0

We multiply parentheses

4y-(-2(5y-7)+8y)+16=0



We calculate terms in parentheses: -(-2(5y-7)+8y), so:

-2(5y-7)+8y

We add all the numbers together, and all the variables

8y-2(5y-7)

We multiply parentheses

8y-10y+14

We add all the numbers together, and all the variables

-2y+14

Back to the equation:

-(-2y+14)



We get rid of parentheses

4y+2y-14+16=0

We add all the numbers together, and all the variables

6y+2=0

We move all terms containing y to the left, all other terms to the right

6y=-2

y=-2/6

y=-1/3

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