3u-6+2(4u+2)=-5(u+4)

Solution for 3u-6+2(4u+2)=-5(u+4) equation:

3u-6+2(4u+2)=-5(u+4)

We move all terms to the left:

3u-6+2(4u+2)-(-5(u+4))=0

We multiply parentheses

3u+8u-(-5(u+4))+4-6=0


We calculate terms in parentheses: -(-5(u+4)), so:

-5(u+4)

We multiply parentheses

-5u-20

Back to the equation:

-(-5u-20)


We add all the numbers together, and all the variables

11u-(-5u-20)-2=0

We get rid of parentheses

11u+5u+20-2=0

We add all the numbers together, and all the variables

16u+18=0

We move all terms containing u to the left, all other terms to the right

16u=-18

u=-18/16

u=-1+1/8