4(y+3)=3y+2+2y

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Solution for 4(y+3)=3y+2+2y equation: 



4(y+3)=3y+2+2y

We move all terms to the left:

4(y+3)-(3y+2+2y)=0

We add all the numbers together, and all the variables

4(y+3)-(5y+2)=0

We multiply parentheses

4y-(5y+2)+12=0

We get rid of parentheses

4y-5y-2+12=0

We add all the numbers together, and all the variables

-1y+10=0

We move all terms containing y to the left, all other terms to the right

-y=-10

y=-10/-1

y=+10

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