4(y+3)=39+2y

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Solution for 4(y+3)=39+2y equation: 



4(y+3)=39+2y

We move all terms to the left:

4(y+3)-(39+2y)=0

We add all the numbers together, and all the variables

4(y+3)-(2y+39)=0

We multiply parentheses

4y-(2y+39)+12=0

We get rid of parentheses

4y-2y-39+12=0

We add all the numbers together, and all the variables

2y-27=0

We move all terms containing y to the left, all other terms to the right

2y=27

y=27/2

y=13+1/2

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